Mathematics (9709)
Topic 6 of 9Cambridge A Levels

Pure 2: Functions and Logarithms

Logarithms, exponential functions, natural logarithm, logarithmic graphs, and solving exponential equations — Pure 2 and 3 material.

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Pure 2: Functions and Logarithms — CIE A Level Mathematics 9709


1. Logarithms


Definition: log_a(x) = y ⟺ aʸ = x


The logarithm is the inverse of the exponential function.


Laws of Logarithms:

  • log_a(xy) = log_a(x) + log_a(y) (product rule)
  • log_a(x/y) = log_a(x) − log_a(y) (quotient rule)
  • log_a(xⁿ) = n log_a(x) (power rule)
  • log_a(1) = 0 (since a⁰ = 1)
  • log_a(a) = 1 (since a¹ = a)

Change of base: $log_a x = rac{log_b x}{log_b a}$ (commonly use base 10 or e)


2. The Natural Logarithm and Euler's Number


e = 2.71828... — Euler's number; base of the natural logarithm.


Natural logarithm: ln x = log_e(x)


Key properties: ln(eˣ) = x and e^(ln x) = x.


Differentiation/integration:

  • d/dx(ln x) = 1/x
  • d/dx(eˣ) = eˣ
  • ∫eˣ dx = eˣ + C
  • ∫(1/x) dx = ln|x| + C

3. Solving Exponential and Logarithmic Equations


Technique 1: Take logs of both sides

3ˣ = 20 → x ln 3 = ln 20 → x = ln 20 / ln 3 = 2.727

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Technique 2: Substitution to form quadratic

2ˣ − 3(2⁻ˣ) = 2 → Multiply by 2ˣ: 2²ˣ − 3 = 2(2ˣ)

Let u = 2ˣ: u² − 2u − 3 = 0 → (u−3)(u+1) = 0 → u = 3 (since u > 0).

2ˣ = 3 → x = ln 3/ln 2 = log₂3 ≈ 1.585


Technique 3: Using ln directly

ln(x+2) + ln(x−1) = ln 10 → ln[(x+2)(x−1)] = ln 10 → (x+2)(x−1) = 10

x² + x − 2 = 10 → x² + x − 12 = 0 → (x+4)(x−3) = 0

x = 3 (x = −4 invalid: ln(negative) undefined). x = 3


4. Logarithmic Graphs — Linearising Data


If y = axⁿ, taking log: log y = log a + n log x (linear: log y vs log x)

If y = aˣ, taking ln: ln y = ln a + x ln b (linear: ln y vs x, for y = abˣ)


Example: Data follows y = kxⁿ. A log-log plot of log y vs log x gives:

  • Gradient = n
  • y-intercept = log k

This technique converts power/exponential relationships into straight lines for easy analysis.


5. Transformations of y = eˣ and y = ln x


Graph of y = eˣ: Always positive; passes through (0,1); asymptote y = 0; increasing.


Graph of y = ln x: Defined for x > 0 only; passes through (1,0); asymptote x = 0.


Key relationship: y = eˣ and y = ln x are reflections in the line y = x.


Transformations:

  • y = e^(2x): horizontal compression factor 2
  • y = eˣ + 3: vertical translation 3 up; asymptote now y = 3
  • y = ln(x−2): translation 2 right; asymptote x = 2, domain x > 2
  • y = −ln x: reflection in x-axis

Key Points to Remember

  • 1Log laws: log(xy)=logx+logy; log(x/y)=logx−logy; log(xⁿ)=nlogx; change of base: log_a(x)=ln(x)/ln(a)
  • 2e≈2.718; ln is log base e; e^(lnx)=x; ln(eˣ)=x — they are inverse functions
  • 3Solving exponential: take logs of both sides; if 2ˣ equation, substitute u=2ˣ to get quadratic
  • 4Logarithmic linearisation: y=axⁿ → log-log plot linear (gradient=n, intercept=loga)
  • 5Domain of ln: x>0 only; asymptote x=0; y=ln(x−a) shifts right by a
  • 6Differentiation: d/dx(ln x)=1/x; d/dx(eˣ)=eˣ; d/dx(e^f(x))=f'(x)e^f(x) (chain rule)

Pakistan Example

Logarithms in Pakistan: Population Growth and Earthquake Magnitudes

Pakistan's population grows exponentially: P = 220 × e^(0.02t) million where t = years after 2020. Taking ln: ln P = ln 220 + 0.02t — a linear relationship between ln(population) and time. Pakistan's population will double when e^(0.02t) = 2 → t = ln2/0.02 = 34.7 years. Earthquake magnitudes use the Richter scale — a logarithmic scale: each unit increase in magnitude = 10× more ground motion amplitude. The 2005 Kashmir earthquake (M 7.6) released about 10^(1.6) ≈ 40 times more energy than a M 6.0 earthquake. Understanding logarithms is essential for Pakistani geologists, epidemiologists (modelling disease spread: R₀ and log-linear epidemic curves), and financial analysts modelling compound interest growth.

Quick Revision Infographic

Mathematics — Quick Revision

Pure 2: Functions and Logarithms

Key Concepts

1Log laws: log(xy)=logx+logy; log(x/y)=logx−logy; log(xⁿ)=nlogx; change of base: log_a(x)=ln(x)/ln(a)
2e≈2.718; ln is log base e; e^(lnx)=x; ln(eˣ)=x — they are inverse functions
3Solving exponential: take logs of both sides; if 2ˣ equation, substitute u=2ˣ to get quadratic
4Logarithmic linearisation: y=axⁿ → log-log plot linear (gradient=n, intercept=loga)
5Domain of ln: x>0 only; asymptote x=0; y=ln(x−a) shifts right by a
6Differentiation: d/dx(ln x)=1/x; d/dx(eˣ)=eˣ; d/dx(e^f(x))=f'(x)e^f(x) (chain rule)

Formulas to Know

Log laws: log(xy)=logx+logy; log(x/y)=logx−logy; log(xⁿ)=nlogx; change of base: log_a(x)=ln(x)/ln(a)
e≈2.718; ln is log base e; e^(lnx)=x; ln(eˣ)=x — they are inverse functions
Solving exponential: take logs of both sides; if 2ˣ equation, substitute u=2ˣ to get quadratic
intercept=loga)
Pakistan Example

Logarithms in Pakistan: Population Growth and Earthquake Magnitudes

Pakistan's population grows exponentially: P = 220 × e^(0.02t) million where t = years after 2020. Taking ln: ln P = ln 220 + 0.02t — a linear relationship between ln(population) and time. Pakistan's population will double when e^(0.02t) = 2 → t = ln2/0.02 = 34.7 years. Earthquake magnitudes use the Richter scale — a logarithmic scale: each unit increase in magnitude = 10× more ground motion amplitude. The 2005 Kashmir earthquake (M 7.6) released about 10^(1.6) ≈ 40 times more energy than a M 6.0 earthquake. Understanding logarithms is essential for Pakistani geologists, epidemiologists (modelling disease spread: R₀ and log-linear epidemic curves), and financial analysts modelling compound interest growth.

SeekhoAsaan.com — Free RevisionPure 2: Functions and Logarithms Infographic

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